2x^2-14x-39=0

Solution for 2x^2-14x-39=0 equation:

2x^2-14x-39=0

a = 2; b = -14; c = -39;
Δ = b2-4ac
Δ = -142-4·2·(-39)
Δ = 508
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{508}=\sqrt{4*127}=\sqrt{4}*\sqrt{127}=2\sqrt{127}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{127}}{2*2}=\frac{14-2\sqrt{127}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{127}}{2*2}=\frac{14+2\sqrt{127}}{4}
$